## Tuesday, November 17, 2009

### Irodov Problem 1.353

As seen from AB's reference frame: A'B' is moving from left to right with a speed v and so has a length of . AB is at rest has a length of l0.

The distance traveled by A'B' when A and A' align is and so the time taken is

The distance traveled by A'B' when B and B' align is l0 and so the time taken is l0/v.

As seen from A'B''s reference frame: AB is moving from right to left at a speed v and so has a length of . A'B' is at rest and has a length of l0.

The distance traveled by AB when B and B' align is and hence the time required is .

The distance traveled by AB when A and A' align is lo and so the time required is lo/v.

Isn't it interesting that according to AB, A and A' align first and then B and B' while according to A'B', B and B' align first and then A and A'. This demonstrates that in relativistic mechanics sequence of events as seen by different observers may in fact be different!

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